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Ajutor ! Exercitiu Matematica

 
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Post Posted: 05-10-2014, 15:19:08 | Translate post to: ... (Click for more languages)

Imi rezolva cineva urmatorul exercitiu ? :

a+b = 12
ab=24

Sa se calculeze :
A la a 2 a + B la a 2 a
A la a 3 a + B la a 3 a
A la a 4 a + B la a 4 a
A la a 6 a + B la a 6 a

Si : 1 supra A + 1 supra B
supra - impartit

Si 1 supra radical din 3 totul la -3 este egal cu ?

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Fough

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Post Posted: 06-10-2014, 09:23:32 | Translate post to: ... (Click for more languages)

a+b = 12
ab=24

Sa se calculeze :
A la a 2 a + B la a 2 a =(a+b)^2-2ab=144-48=96
A la a 3 a + B la a 3 a =(a+b)*(a^2-ab+b^2)=12*84=1008
A la a 4 a + B la a 4 a =(a^2+b^2)^2-2a^2b^2=96^2-2*24^2=8064
A la a 6 a + B la a 6 a =(a^3+b^3)^2-2a^3b^3=1008^2-2*24^3=988416

Si : 1 supra A + 1 supra B =(a+b)/(a*b)=1/2
supra - impartit

Si 1 supra radical din 3 totul la -3 =sqrt(3)^3=3sqrt(3) ...sper sa intelegi ce-am scris pe-acolo



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