User
Pass
2FA
 
 

Atentie! Aceasta este versiunea LowFi a topicului! Click aici pentru varianta originala.
Informatica

 
This forum is locked: you cannot post, reply to, or edit topics.   This topic is locked: you cannot edit posts or make replies.    Freakz Forum Index -> Trash Bin -> Trash -> Homework zone
Author Message1516
Valentin001

[Mentally Stable]
Post Posted: 14-01-2018, 12:45:08 | Translate post to: ... (Click for more languages)
Sã se afiºeze toate numerele naturale mai mici sau egale cu 2000 care împãrþite la 24, 30,
18 dau restul 7.
Daca se poate, prin subprogram as vrea!
Multumesc!
0 0
  
tudor1297

[shefu' la luptatori]
Post Posted: 14-01-2018, 13:09:33 | Translate post to: ... (Click for more languages)
#include<iostream>
using namespace std;
void subprogram()
{
int i;
for(i=1; i<=2000; i++)
if(i%18==7 && i%24==7 && i%30==7)
cout<<i;
}

void main()
{
subprogram();
}




Sper ca n.am gresit nimic, n.am mai scris o linie de cod de 3 ani -

Mai exista o metoda ceva mai desteapta, si anume sa gasesti cel mai mic multiplu comun si sa afisezi multiplii nunumarului asta + 7. Adica cmmmc+7, 2*cmmmc+7 etc.
cmmmc e 360 pt 18,24,30 deci subprogramul ar deveni ceva de genul:
void subprogram()
{
int i;
for(i=0; 360*i +7 <= 2000; i++)
cout<<360*i +7;
}
0 0
  
Valentin001

[Mentally Stable]
Post Posted: 14-01-2018, 13:39:15 | Translate post to: ... (Click for more languages)
Multumesc de ajutor !
1 0
  
This forum is locked: you cannot post, reply to, or edit topics.   This topic is locked: you cannot edit posts or make replies.    Freakz Forum Index -> Trash Bin -> Trash -> Homework zone  


The time now is 27-04-2025, 15:32:46
Copyright info

Based on phpBB ro/com
B

 
  
 







I forgot my password