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Andreidom

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Post Posted: 24-07-2011, 00:01:51 | Translate post to: ... (Click for more languages)

Sunt elev in clasa 6 si trec in a-7a si am probleme la mate in legatura cu proportionalitatea si invers proportionalitatea.


{x;y;z} dp {2;23;10}

x/2=y/23=z/10


Cum fac???? -

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T4 *Cost1n

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Post Posted: 24-07-2011, 00:09:30 | Translate post to: ... (Click for more languages)

le aduci la acelasi numitor. si o sa iti dea(zic la intamplare) 14x=45y=23z
zic eu. sper sa fie bine -


You gave him what he asked for.
I gave him what he needed.
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Andreidom

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Post Posted: 24-07-2011, 00:12:03 | Translate post to: ... (Click for more languages)

Asta e un exemplu. Eu ziceam in general!
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bKL

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Post Posted: 10-09-2011, 14:38:57 | Translate post to: ... (Click for more languages)

Quote:
{x;y;z} dp {2;23;10} (egalezi cu "K") => x=2k , y=23k , z=10k

x/2=y/23=z/10
=> 2k/2 = 23k/23=10k/10 , aduci la acelasi numitor si il afli pe "K" ,dupa care inlocuiesti sus in functie de ce rezultat are "k"



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Andreidom

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Post Posted: 11-09-2011, 12:42:38 | Translate post to: ... (Click for more languages)

Dar cum le aduc?
Aratim cum sa le aduc.

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