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Math trick [64=65]
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Malpraxxiss

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Post Posted: 06-06-2007, 07:13:51 | Translate post to: ... (Click for more languages)

https://youtube.com/watch?v=7hHZr91XWbw:


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Kre@toR

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Post Posted: 06-06-2007, 07:57:11 | Translate post to: ... (Click for more languages)

E destept omu asta man --- prea tare -


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Post Posted: 06-06-2007, 08:25:37 | Translate post to: ... (Click for more languages)

parca a fost la canguru asta - oricum o stiam -


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Malpraxxiss

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Post Posted: 06-06-2007, 10:24:18 | Translate post to: ... (Click for more languages)

O sa postez mai pe seara solutia la paradox, ca vad ca nimeni nu are nicio ideie -
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Alpha_Kill3r

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Post Posted: 06-06-2007, 16:22:45 | Translate post to: ... (Click for more languages)

Luand fiecare unitate in parte suma ariilor iese aceiasi deci trebuie sa presupunem cumva ca la mutarea acestor piese din froma de patrat in dreptunghi undeva castigam 1 cm patrat. Probabil ca undeva se formeaza un spatiu ...dar nu stiu exact -

Populatia Pamantului e in crestere...Inteligenta ramane constanta
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Post Posted: 06-06-2007, 19:08:48 | Translate post to: ... (Click for more languages)

Alpha_Kill3r wrote:
Probabil ca undeva se formeaza un spatiu ...dar nu stiu exact -

Exact asta se si intampla, animatia e putin trasa de par sa para totul in regula -


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Post Posted: 06-06-2007, 19:35:33 | Translate post to: ... (Click for more languages)

La aceasi chetie ma gandeam si eu, cred ca intro revista canguru am gasit o chestie deasta, sunt jocuri ce tin de logica -
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Malpraxxiss

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Post Posted: 07-06-2007, 08:40:19 | Translate post to: ... (Click for more languages)

Paradoxul se explica prin faptul ca fragmentele nu se potrivesc exact dupa diagonala mai lunga, unde exista un spatiu egal cu o unitate patrata. Observati ca lungimile segmentelor de dreapta din aceste figure sunt termini ai sirului lui Fibonacci. In fapt, putem taia un patratul astfel incat segmentele sa fie termini consecutive in orice sir aditiv, si vom obtine intotdeauna o forma a paradoxului, desi in unele cazuri dreptunghiul cel lung va castiga in arie, in altele va pierde, din cauza unor incalecari in lungul diagonalei principale. Aceasta reflecta faptul ca termenii consecutive ai oricarui sir aditiv sunt intr-un raport care este alternative mai mare sau mai mic decat φ.
Singura maniera de a sectiona un patrat , in asa fel incat sa nu avem pierdere sau castig de arie la dreptunghi, consta in al taia dupa segmente a caror lungimi este luata din sirul aditiv 1,φ, φ +1, 2φ+1, 3φ+2,… Alta cale de a scrie acest sir este 1, φ , φ2 , φ3 , φ4 , …Este singurul sir aditiv in care raportul dintre orice pereche de termini consecutive este constant. (Raportul este, fireste, φ).

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Zippy

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Post Posted: 07-06-2007, 09:33:34 | Translate post to: ... (Click for more languages)

uhh
tocilarule -

eu stiu sa demonstrez ca 2+2=5 -

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Malpraxxiss

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Post Posted: 07-06-2007, 10:12:00 | Translate post to: ... (Click for more languages)

Zippy wrote:
uhh
tocilarule -

eu stiu sa demonstrez ca 2+2=5 -


E pe acelasi principiu
Oricum 2x2 = 2+2 asa ca ... -)

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Post Posted: 07-06-2007, 10:16:48 | Translate post to: ... (Click for more languages)

eu o stiam pe aia cu 1 + 1 = 0 ... o intrebare..sunteti destepti daca o faceti pe asta...ce numar inmultit cu 4 = 3 -
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DusTeR

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Post Posted: 07-06-2007, 10:25:50 | Translate post to: ... (Click for more languages)

0,75 * 4 = 3 -

The Empire Strikes Back // tru story!

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Zippy

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Post Posted: 07-06-2007, 10:25:52 | Translate post to: ... (Click for more languages)

nu e legat de patratele

2+2=5
adik 4=5 da?

presupunem

8-8=10-10 asa-i? sau 0 nu e egal cu 0?

scoatem in ambele cate un factor comun:
4(2-2)=5(2-2)

2-2 din ambele parti se reduce

ramane 4=5

adik 2+2=5

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DusTeR

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Post Posted: 07-06-2007, 10:26:51 | Translate post to: ... (Click for more languages)

zippy, citeshte aici http://forum.wow-freakz.com/viewtopic.php?t=7921&&lowfi=0&&Math-trick-%5B-2x2=5%5D

n-ai voie sa imparti cu 2 - 2 pentru ca e 0 -


The Empire Strikes Back // tru story!

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Zippy

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Post Posted: 07-06-2007, 10:29:37 | Translate post to: ... (Click for more languages)

e o demonstratie -
nu am zis ca e corecta demonstratia -

lol tuamne c s-a complicat ala din filmuletz -

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