program matrice

gigelu · Posted: 03-02-2013, 14:49:09 | Translate post to: ... (Click for more languages)

Doresc si eu un program sau sfaturi cam sa-l fac care sa faca asta :
Se citesc 2 nr naturale (n si m)care constituie o matrice cu n linii si m coloane astfel incat fiecare element A(i,j) memoreaza cea mai mica valoare dintre valoare indicilor i si j (1<j<m) si (1<i<n) Se da n=4 si m=5. Daca mi-l puteti face in codeblocks sau in c++ (si il adaptez eu).sau doar sami ziceti in cuvinte ce am de facut.
MUltumesc

Raster · Posted: 03-02-2013, 17:11:41 | Translate post to: ... (Click for more languages)

Code:

#include <iostream>
#include <cstdlib>
using namespace std;

int main()
{
int m,n,i,j,a[10][9];
cout<<"m="; cin>>m;
cout<<"n="; cin>>n;
for (i=0;i<m;i++)
for (j=0;j<n;j++)
{
cout<<"a["<<i+1<<','<<j+1<<"]=";
cin>>a[i][j];
}
for (i=0;i<m;i++)
{
for (j=0;j<n;j++)
cout<<a[i][j]<<' ';
cout<<endl;
}
system("PAUSE");
return 0;
}

LE: A, wait, fail, asta doar iti afiseaza matricea n/m, n-am citit bine.

воронья

mojii · Posted: 03-04-2013, 14:54:35 | Translate post to: ... (Click for more languages)

Tiam facut eu cv dar nu inteleg care e treaba cu conditia asta asta: (1<j<m) si (1<i<n) . Daca nu e true eu am mmorat in a(i,j) 0.

Code:

#include <iostream>

using namespace std;

int main()
{
int m = 0,
   i = 0,
   j = 0,
   n = 0,
   a[15][15];

cout<<"n="; cin>>n;
cout<<"m="; cin>>m;

for (i=0;i<n;i++)
   for (j=0;j<m;j++){
      if ((i > j) && (j < m) && (i < n) && (i > 1) && (j >1))
         a[i][j] = j;
      else if ((j > i) && (j < m) && (i < n) && (i > 1) && (j >1))
         a[i][j] = i;
      else a[i][j] = 0;
}
for (i=0;i<n;i++){
   for (j=0;j<m;j++)
      cout<<a[i][j]<<' ';
cout<<endl;
}

system("PAUSE");
return 0;
}