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Math trick [ 2x2=5]
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Malpraxxiss

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Post Posted: 05-06-2007, 19:43:47 | Translate post to: ... (Click for more languages)

https://youtube.com/watch?v=iKTCTy4UsUg:


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SpeeDAcId

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Post Posted: 05-06-2007, 19:51:06 | Translate post to: ... (Click for more languages)

2x2=5 aia e gresita -

SUNT NEBUUUUN!!!
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Malpraxxiss

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Post Posted: 05-06-2007, 19:52:44 | Translate post to: ... (Click for more languages)

no shit - zimi cu ce a gresit ala la calcul, sau poate chiar asa e, mai stii... -
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Ei8hter

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Post Posted: 05-06-2007, 20:03:16 | Translate post to: ... (Click for more languages)

haha , uite topicuri deastea sunt interesante . Stiam si eu o faza deasta.

[quote="dudette"]esti cel mai normal dintre noi.clar -)[/quote]
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Pepsi

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Post Posted: 05-06-2007, 20:05:19 | Translate post to: ... (Click for more languages)

L-am facut pe foaie.....
la sfarsit(daca inlocuiesti) ajungi la calculul:
4x (5-1-4) = 5x (5-1-4)
In acest caz s-a simplificat insa......Calculul este adevarat...
4x (5-1-4)=0
5x (5-1-4)=0
Rezulta ca 4x (5-1-4) = 5x (5-1-4)
Asta nu inseamna ca 4=5.

Asa pot sa modific si eu -

987x (5-1-4) = 3x (5-1-4)
Asta nu inseamna ca 987 = 3 -

Acolo nu trebuie simplificat...
Io cred ca asta e explicatia..





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Malpraxxiss

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Post Posted: 05-06-2007, 20:06:33 | Translate post to: ... (Click for more languages)

Asa si care e explicatia matematica -
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Pepsi

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Post Posted: 05-06-2007, 20:08:28 | Translate post to: ... (Click for more languages)

Asta -
Acolo nu trebuia simplificat.

deoarece paranteza dadea 0 -
Daca paranteza dadea 1 nu mai iesea calculul....

aici vine:
4x0 = 5x0
daca era 4x1=5x1 rationamentul nu mai era corect.
Ce e spus acolo e corect dar nu trebuie simplificata paranteza...





In2 In2: Your username is: in2itiona
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blader

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Post Posted: 05-06-2007, 20:08:43 | Translate post to: ... (Click for more languages)

Conform acelui calcul:
C=B-A/(B-A)<=>1=5-1/(5-4)
Nu exista nici o sansa ca 1=4 -



Dereglat, ca un ceas antic.
Exile the Ninja wrote:
In2ition , esti un carnat afumat. Ada' slanina aici si o felie de pita, te mananc ba.

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Malpraxxiss

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Post Posted: 05-06-2007, 20:09:35 | Translate post to: ... (Click for more languages)

BlaDeR!!!111 wrote:
Conform acelui calcul:
C=B-A/(B-A)<=>1=5-1/(5-4)
Nu exista nici o sansa ca 1=4 -


LOL -) acolo inmulteste o ecuatie cu o alta relatie - nu e nimic gresit

Pepsi a spus bine.
O ecuatie nu se imparte nici odata cu o expresie egala cu 0 -



Last edited by Malpraxxiss on 05-06-2007, 20:10:48; edited 1 time in total
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Pepsi

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Post Posted: 05-06-2007, 20:09:59 | Translate post to: ... (Click for more languages)

BlaDeR!!!111 wrote:
Conform acelui calcul:
C=B-A/(B-A)<=>1=5-1/(5-4)
Nu exista nici o sansa ca 1=4 -

A=4
B=5
C=1

C= B-A
C=5-4
C=1
-





In2 In2: Your username is: in2itiona
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SpeeDAcId

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Post Posted: 05-06-2007, 20:13:07 | Translate post to: ... (Click for more languages)

deci va rog frumos vb si voi romaneste. Eu numai inteleg nimik mai ales cand a inceput pepsi cu formulele alea. Vb si pe intelesul la aia care nu au mai fost la mate din clasa a 9-a -

SUNT NEBUUUUN!!!
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DusTeR

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Post Posted: 05-06-2007, 20:13:55 | Translate post to: ... (Click for more languages)

SpeeDAcId: eu m-ash abtine de la asemenea comentarii - te faci singur de ras -

The Empire Strikes Back // tru story!

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hasbeo
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Post Posted: 05-06-2007, 20:14:18 | Translate post to: ... (Click for more languages)

Hmmm e o simpla cascadorie.Cred k se poate face o chestie d-asta shi cu 9*9=100
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Pepsi

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Post Posted: 05-06-2007, 20:14:20 | Translate post to: ... (Click for more languages)

lol -
Io sunt la olimpiade si iti spun Malpraxiss ca ce a scris ala nu e corect...
Il intreb si pe taicamiu in seara asta....





In2 In2: Your username is: in2itiona
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In2ition

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Post Posted: 05-06-2007, 20:18:07 | Translate post to: ... (Click for more languages)

daca se imparte prin (B-C-A) , se pierde o solutie
daca faceti calcului vedeti ca A * 0 = B * 0 > 0 = 0
fking freaks


We stop looking for monsters under the bed when we realize they're inside of us.

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no really, dacã nu era așa țãrancã, și dacã era în bucurești, o luam de nevastã

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