( Rezolvat ) problema geometrie cls a 7-a

mD@ · Posted: 06-11-2007, 09:53:15 | Translate post to: ... (Click for more languages)

nu stiu sa fac deci

Calculati aria unuui patrulater ortodiagonal avand diagonalele egale cu 40 cm si 48 cm

illuSion · Posted: 06-11-2007, 10:07:18 | Translate post to: ... (Click for more languages)

A=960
patrulater ortodiagonal e rombu`

mD@ · Posted: 06-11-2007, 11:36:39 | Translate post to: ... (Click for more languages)

thx

illuSion · Posted: 06-11-2007, 11:42:57 | Translate post to: ... (Click for more languages)

npc

Shocker · Posted: 06-11-2007, 12:28:15 | Translate post to: ... (Click for more languages)

Explica-i si cum ai facut, asta e mai important

Aria unui patrulater ortodiagonal ABCD este egala cu semiprodusul diagonalelor
AABCD=(AC*BD)/2

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mD@ · Posted: 06-11-2007, 19:13:00 | Translate post to: ... (Click for more languages)

stiu cum dar nu stiam ce e 4l orto nush ce .! diagonala1 . diagonala2 supra 2 = d1.d2 supra 2 = 40.48 supra 2 simplificam 40 cu 2 ne da 20 .48 si egal cu 960 cm patrati

Br3aK · Posted: 06-11-2007, 19:50:02 | Translate post to: ... (Click for more languages)

Mah deci sa ti minte cel mai important
AABCD =latura * intaltime = baza * inaltime in caz ca faci cu inaltime

AABCD=diagonala 1 * diagonala 2 supra 2
AABCD=40 * 48 supra 2 , se simplifica 40 cu 2 =20 * 48 = 960 cm2

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