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Powasumuch.

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Post Posted: 10-11-2012, 11:25:11 | Translate post to: ... (Click for more languages)

(x-2)(3x-4)
(6x+1)(2x-2)
2(3|2x+5|-4)-7<=3
2x+4x+6x+...+18x=360
Mersi anticipat.

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J0hny

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Post Posted: 11-11-2012, 18:49:30 | Translate post to: ... (Click for more languages)

(x-2) (3-2)
(2x+1) (3x-2)
cred ca astea sunt la primele 2 la celelalte nu mai stiu
.




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Reyes

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Post Posted: 12-11-2012, 00:42:42 | Translate post to: ... (Click for more languages)

primele 2 nu inteleg ce trebuie sa faci cu ele... sa le desfaci?
al treilea ai modul in el? ca nu prea inteleg din ce ai scris acolo

Ultimul e simplu

2x+4x+6x+...+18x=360

dai factor comun pe 2x
2x*(1+2+3+...9)=360

1+2+3+...+9 = n(n+1)/2 = 9(9+1)/2=90/2=45

2x*45=360
x=360/90
x=4

Succes! -




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