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matrici c++

 
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MadalinXd

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Post Posted: 20-10-2014, 16:30:00 | Translate post to: ... (Click for more languages)

As dori si eu cateva idei cum sa rezolv aceasta problema cu matrici.

1.Sa se afiseze simetrica matricei fata de axa verticala care trece prin centrul matricei.

Code:

1 2 3 4 5
6 7 8 9 10


Eu am incercat cu aceasta varianta dar nu functioneaza:
Code:

      for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=m;j++)
            {
               if(j<(m+1)/2)
               {
                   aux=v[i][j];
                   v[i][j]=v[i][m-i+1];
                   v[i][m-i+1]=aux;
               }
            }
     }

i=linia
j=coloana
n=nr de linii
j=nr de coloane;



Nu vreau mura in gura doar o idee cum sa-l fac de unde sa incep.

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tudor1297

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Post Posted: 20-10-2014, 16:45:20 | Translate post to: ... (Click for more languages)

stai putin ca nu inteleg
pentru exemplu ala ar trebui sa afisezi asa?

5 4 3 2 1
10 9 8 7 6


banuiesc ca asta tre sa faci


dar vezi ca nu trebuie neaparat sa modifici matricea. adica ai putea pur si simplu sa o afisezi, numai ca in alta ordine.
poti face asta asa:

Quote:


for(i=1;i<=n;++i)
for(j=m;j>=1;--j)
cout<< v[i][j];




anyway, nici ideea ta nu e gresita, doar ca faci niste operatii inutile -

greseala ta e ca ai pus v[i][m-i+1] in loc de v[i][m-j+1]
din cauza asta nu-ti merge programul




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Last edited by tudor1297 on 20-10-2014, 16:55:07; edited 1 time in total
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MadalinXd

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Post Posted: 20-10-2014, 16:52:27 | Translate post to: ... (Click for more languages)

Da.
T/C am rezolvat.

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tudor1297

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Post Posted: 20-10-2014, 16:56:19 | Translate post to: ... (Click for more languages)

ah
am editat postul, dar fix inainte sa dau send am resetat pagina din greseala si-a trebuit sa scriu iar -




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R3dBuLL
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Post Posted: 11-01-2015, 18:28:18 | Translate post to: ... (Click for more languages)

@meeeeeow dai TC daca poti -


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Topic is closed, you cannot post any messages in it anymore

Locked by PsychoLove, 25 January 2015 21:01



 
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